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(2x+7)+(4x+3)=112
We move all terms to the left:
(2x+7)+(4x+3)-(112)=0
We get rid of parentheses
2x+4x+7+3-112=0
We add all the numbers together, and all the variables
6x-102=0
We move all terms containing x to the left, all other terms to the right
6x=102
x=102/6
x=17
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