(2x+7u)(x-4u-5)=0

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Solution for (2x+7u)(x-4u-5)=0 equation: 


Simplifying
(2x + 7u)(x + -4u + -5) = 0

Reorder the terms:
(7u + 2x)(x + -4u + -5) = 0

Reorder the terms:
(7u + 2x)(-5 + -4u + x) = 0

Multiply (7u + 2x) * (-5 + -4u + x)
(7u * (-5 + -4u + x) + 2x * (-5 + -4u + x)) = 0
((-5 * 7u + -4u * 7u + x * 7u) + 2x * (-5 + -4u + x)) = 0

Reorder the terms:
((-35u + 7ux + -28u2) + 2x * (-5 + -4u + x)) = 0
((-35u + 7ux + -28u2) + 2x * (-5 + -4u + x)) = 0
(-35u + 7ux + -28u2 + (-5 * 2x + -4u * 2x + x * 2x)) = 0

Reorder the terms:
(-35u + 7ux + -28u2 + (-8ux + -10x + 2x2)) = 0
(-35u + 7ux + -28u2 + (-8ux + -10x + 2x2)) = 0

Reorder the terms:
(-35u + 7ux + -8ux + -28u2 + -10x + 2x2) = 0

Combine like terms: 7ux + -8ux = -1ux
(-35u + -1ux + -28u2 + -10x + 2x2) = 0

Solving
-35u + -1ux + -28u2 + -10x + 2x2 = 0

Solving for variable 'u'.

The solution to this equation could not be determined.

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