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(2x+8)(2x+10)=63
We move all terms to the left:
(2x+8)(2x+10)-(63)=0
We multiply parentheses ..
(+4x^2+20x+16x+80)-63=0
We get rid of parentheses
4x^2+20x+16x+80-63=0
We add all the numbers together, and all the variables
4x^2+36x+17=0
a = 4; b = 36; c = +17;
Δ = b2-4ac
Δ = 362-4·4·17
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-32}{2*4}=\frac{-68}{8} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+32}{2*4}=\frac{-4}{8} =-1/2 $
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