(2x+8)(2x+6)=96

Solution for (2x+8)(2x+6)=96 equation:

(2x+8)(2x+6)=96

We move all terms to the left:

(2x+8)(2x+6)-(96)=0

We multiply parentheses ..

(+4x^2+12x+16x+48)-96=0

We get rid of parentheses

4x^2+12x+16x+48-96=0

We add all the numbers together, and all the variables

4x^2+28x-48=0

a = 4; b = 28; c = -48;
Δ = b2-4ac
Δ = 282-4·4·(-48)
Δ = 1552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1552}=\sqrt{16*97}=\sqrt{16}*\sqrt{97}=4\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{97}}{2*4}=\frac{-28-4\sqrt{97}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{97}}{2*4}=\frac{-28+4\sqrt{97}}{8}
$