(2x+8)(4x-3)=0

Solution for (2x+8)(4x-3)=0 equation:

(2x+8)(4x-3)=0

We multiply parentheses ..

(+8x^2-6x+32x-24)=0

We get rid of parentheses

8x^2-6x+32x-24=0

We add all the numbers together, and all the variables

8x^2+26x-24=0

a = 8; b = 26; c = -24;
Δ = b2-4ac
Δ = 262-4·8·(-24)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-38}{2*8}=\frac{-64}{16}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+38}{2*8}=\frac{12}{16}
=3/4
$