(2x+8)(5x-7)-(25x*x-49)=0

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Solution for (2x+8)(5x-7)-(25x*x-49)=0 equation: 


Simplifying
(2x + 8)(5x + -7) + -1(25x * x + -49) = 0

Reorder the terms:
(8 + 2x)(5x + -7) + -1(25x * x + -49) = 0

Reorder the terms:
(8 + 2x)(-7 + 5x) + -1(25x * x + -49) = 0

Multiply (8 + 2x) * (-7 + 5x)
(8(-7 + 5x) + 2x * (-7 + 5x)) + -1(25x * x + -49) = 0
((-7 * 8 + 5x * 8) + 2x * (-7 + 5x)) + -1(25x * x + -49) = 0
((-56 + 40x) + 2x * (-7 + 5x)) + -1(25x * x + -49) = 0
(-56 + 40x + (-7 * 2x + 5x * 2x)) + -1(25x * x + -49) = 0
(-56 + 40x + (-14x + 10x2)) + -1(25x * x + -49) = 0

Combine like terms: 40x + -14x = 26x
(-56 + 26x + 10x2) + -1(25x * x + -49) = 0

Multiply x * x
-56 + 26x + 10x2 + -1(25x2 + -49) = 0

Reorder the terms:
-56 + 26x + 10x2 + -1(-49 + 25x2) = 0
-56 + 26x + 10x2 + (-49 * -1 + 25x2 * -1) = 0
-56 + 26x + 10x2 + (49 + -25x2) = 0

Reorder the terms:
-56 + 49 + 26x + 10x2 + -25x2 = 0

Combine like terms: -56 + 49 = -7
-7 + 26x + 10x2 + -25x2 = 0

Combine like terms: 10x2 + -25x2 = -15x2
-7 + 26x + -15x2 = 0

Solving
-7 + 26x + -15x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-7 + 5x)(1 + -3x) = 0


Subproblem 1
Set the factor '(-7 + 5x)' equal to zero and attempt to solve:

Simplifying
-7 + 5x = 0

Solving
-7 + 5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 5x = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 5x = 0 + 7
5x = 0 + 7

Combine like terms: 0 + 7 = 7
5x = 7

Divide each side by '5'.
x = 1.4

Simplifying
x = 1.4

Subproblem 2
Set the factor '(1 + -3x)' equal to zero and attempt to solve:

Simplifying
1 + -3x = 0

Solving
1 + -3x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3x = 0 + -1
-3x = 0 + -1

Combine like terms: 0 + -1 = -1
-3x = -1

Divide each side by '-3'.
x = 0.3333333333

Simplifying
x = 0.3333333333
Solution
x = {1.4, 0.3333333333}

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