(2x+8)(6x+4)=0

Solution for (2x+8)(6x+4)=0 equation:

(2x+8)(6x+4)=0

We multiply parentheses ..

(+12x^2+8x+48x+32)=0

We get rid of parentheses

12x^2+8x+48x+32=0

We add all the numbers together, and all the variables

12x^2+56x+32=0

a = 12; b = 56; c = +32;
Δ = b2-4ac
Δ = 562-4·12·32
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-40}{2*12}=\frac{-96}{24}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+40}{2*12}=\frac{-16}{24}
=-2/3
$