(2x+8)+(2x+7)+(2x)=(2x)+(2x)+(3x+6)

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Solution for (2x+8)+(2x+7)+(2x)=(2x)+(2x)+(3x+6) equation: 



(2x+8)+(2x+7)+(2x)=(2x)+(2x)+(3x+6)

We move all terms to the left:

(2x+8)+(2x+7)+(2x)-((2x)+(2x)+(3x+6))=0

We add all the numbers together, and all the variables

2x+(2x+8)+(2x+7)-(2x+2x+(3x+6))=0

We get rid of parentheses

2x+2x+2x-(2x+2x+(3x+6))+8+7=0



We calculate terms in parentheses: -(2x+2x+(3x+6)), so:

2x+2x+(3x+6)

We add all the numbers together, and all the variables

4x+(3x+6)

We get rid of parentheses

4x+3x+6

We add all the numbers together, and all the variables

7x+6

Back to the equation:

-(7x+6)



We add all the numbers together, and all the variables

6x-(7x+6)+15=0

We get rid of parentheses

6x-7x-6+15=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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