(2x+8)+(3x+12)=(7x-36)

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Solution for (2x+8)+(3x+12)=(7x-36) equation: 



(2x+8)+(3x+12)=(7x-36)

We move all terms to the left:

(2x+8)+(3x+12)-((7x-36))=0

We get rid of parentheses

2x+3x-((7x-36))+8+12=0



We calculate terms in parentheses: -((7x-36)), so:

(7x-36)

We get rid of parentheses

7x-36

Back to the equation:

-(7x-36)



We add all the numbers together, and all the variables

5x-(7x-36)+20=0

We get rid of parentheses

5x-7x+36+20=0

We add all the numbers together, and all the variables

-2x+56=0

We move all terms containing x to the left, all other terms to the right

-2x=-56

x=-56/-2

x=+28

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