(2x+8)+(3x+16)+(3x+16)+4x-18)+(3x-7)+(2x+25)=720

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Solution for (2x+8)+(3x+16)+(3x+16)+4x-18)+(3x-7)+(2x+25)=720 equation: 



(2x+8)+(3x+16)+(3x+16)+4x-18)+(3x-7)+(2x+25)=720

We move all terms to the left:

(2x+8)+(3x+16)+(3x+16)+4x-18)+(3x-7)+(2x+25)-(720)=0

We add all the numbers together, and all the variables

4x+(2x+8)+(3x+16)+(3x+16)-18)+(3x-7)+(2x=0

We get rid of parentheses

4x+2x+3x+3x-18)+(3x-7)+(2x+8+16+16=0

We add all the numbers together, and all the variables

12x-18)+(3x-7)+(2x+40=0

We move all terms containing x to the left, all other terms to the right

12x-18)+(3x-7)+(2x=-40

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