(2x+8)+(3x+16)+(4x-18)+(3x-7)+(2x+25)=540

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Solution for (2x+8)+(3x+16)+(4x-18)+(3x-7)+(2x+25)=540 equation: 



(2x+8)+(3x+16)+(4x-18)+(3x-7)+(2x+25)=540

We move all terms to the left:

(2x+8)+(3x+16)+(4x-18)+(3x-7)+(2x+25)-(540)=0

We get rid of parentheses

2x+3x+4x+3x+2x+8+16-18-7+25-540=0

We add all the numbers together, and all the variables

14x-516=0

We move all terms containing x to the left, all other terms to the right

14x=516

x=516/14

x=36+6/7

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