(2x+8)+(3x-20)+x=400

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Solution for (2x+8)+(3x-20)+x=400 equation: 



(2x+8)+(3x-20)+x=400

We move all terms to the left:

(2x+8)+(3x-20)+x-(400)=0

We add all the numbers together, and all the variables

x+(2x+8)+(3x-20)-400=0

We get rid of parentheses

x+2x+3x+8-20-400=0

We add all the numbers together, and all the variables

6x-412=0

We move all terms containing x to the left, all other terms to the right

6x=412

x=412/6

x=68+2/3

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