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(2x+8)/(5x-4x+4)=2
We move all terms to the left:
(2x+8)/(5x-4x+4)-(2)=0
Domain of the equation: (5x-4x+4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x-4x!=-4
x∈R
(2x+8)/(x+4)-2=0
We multiply all the terms by the denominator
(2x+8)-2*(x+4)=0
We multiply parentheses
(2x+8)-2x-8=0
We get rid of parentheses
2x-2x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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