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(2x+8/6)+8=x-4
We move all terms to the left:
(2x+8/6)+8-(x-4)=0
We add all the numbers together, and all the variables
(+2x+8/6)-(x-4)+8=0
We get rid of parentheses
2x-x+4+8+8/6=0
We multiply all the terms by the denominator
2x*6-x*6+8+4*6+8*6=0
We add all the numbers together, and all the variables
2x*6-x*6+80=0
Wy multiply elements
12x-6x+80=0
We add all the numbers together, and all the variables
6x+80=0
We move all terms containing x to the left, all other terms to the right
6x=-80
x=-80/6
x=-13+1/3
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