(2x+9)(4x+3)=8x2+12

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Solution for (2x+9)(4x+3)=8x2+12 equation: 



(2x+9)(4x+3)=8x^2+12

We move all terms to the left:

(2x+9)(4x+3)-(8x^2+12)=0

We get rid of parentheses

-8x^2+(2x+9)(4x+3)-12=0

We multiply parentheses ..

-8x^2+(+8x^2+6x+36x+27)-12=0

We get rid of parentheses

-8x^2+8x^2+6x+36x+27-12=0

We add all the numbers together, and all the variables

42x+15=0

We move all terms containing x to the left, all other terms to the right

42x=-15

x=-15/42

x=-5/14

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