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(2x+9)(7x-3)=0
We multiply parentheses ..
(+14x^2-6x+63x-27)=0
We get rid of parentheses
14x^2-6x+63x-27=0
We add all the numbers together, and all the variables
14x^2+57x-27=0
a = 14; b = 57; c = -27;
Δ = b2-4ac
Δ = 572-4·14·(-27)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-69}{2*14}=\frac{-126}{28} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+69}{2*14}=\frac{12}{28} =3/7 $
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