(2x+9)+(2x+9)+(x-5)+(x-5)=50

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Solution for (2x+9)+(2x+9)+(x-5)+(x-5)=50 equation: 



(2x+9)+(2x+9)+(x-5)+(x-5)=50

We move all terms to the left:

(2x+9)+(2x+9)+(x-5)+(x-5)-(50)=0

We get rid of parentheses

2x+2x+x+x+9+9-5-5-50=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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