(2x+9)/5=(7x-5)/6

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Solution for (2x+9)/5=(7x-5)/6 equation: 



(2x+9)/5=(7x-5)/6

We move all terms to the left:

(2x+9)/5-((7x-5)/6)=0

We calculate fractions


2x/()+(-((7x-5)*5)/()=0



We calculate terms in parentheses: +(-((7x-5)*5)/(), so:

-((7x-5)*5)/(

We multiply all the terms by the denominator


-((7x-5)*5)



We calculate terms in parentheses: -((7x-5)*5), so:

(7x-5)*5

We multiply parentheses

35x-25

Back to the equation:

-(35x-25)



We get rid of parentheses

-35x+25

Back to the equation:

+(-35x+25)



We get rid of parentheses

2x/()-35x+25=0

We multiply all the terms by the denominator


2x-35x*()+25*()=0

We add all the numbers together, and all the variables

2x-35x*()=0

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