(2x+9)=(3x+35)/2

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Solution for (2x+9)=(3x+35)/2 equation: 



(2x+9)=(3x+35)/2

We move all terms to the left:

(2x+9)-((3x+35)/2)=0

We get rid of parentheses

2x-((3x+35)/2)+9=0

We multiply all the terms by the denominator


2x*2)-((3x+35)+9*2)=0

We add all the numbers together, and all the variables

2x*2)-((3x+35)=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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