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(2x+9)x=260
We move all terms to the left:
(2x+9)x-(260)=0
We multiply parentheses
2x^2+9x-260=0
a = 2; b = 9; c = -260;
Δ = b2-4ac
Δ = 92-4·2·(-260)
Δ = 2161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2161}}{2*2}=\frac{-9-\sqrt{2161}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2161}}{2*2}=\frac{-9+\sqrt{2161}}{4} $
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