(2x+92)=(3x+63)

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Solution for (2x+92)=(3x+63) equation: 



(2x+92)=(3x+63)

We move all terms to the left:

(2x+92)-((3x+63))=0

We get rid of parentheses

2x-((3x+63))+92=0



We calculate terms in parentheses: -((3x+63)), so:

(3x+63)

We get rid of parentheses

3x+63

Back to the equation:

-(3x+63)



We get rid of parentheses

2x-3x-63+92=0

We add all the numbers together, and all the variables

-1x+29=0

We move all terms containing x to the left, all other terms to the right

-x=-29

x=-29/-1

x=+29

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