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(2x+x+3)/5=15
We move all terms to the left:
(2x+x+3)/5-(15)=0
We add all the numbers together, and all the variables
(3x+3)/5-15=0
We multiply all the terms by the denominator
(3x+3)-15*5=0
We add all the numbers together, and all the variables
(3x+3)-75=0
We get rid of parentheses
3x+3-75=0
We add all the numbers together, and all the variables
3x-72=0
We move all terms containing x to the left, all other terms to the right
3x=72
x=72/3
x=24
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