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(2x-(5/x))=99
We move all terms to the left:
(2x-(5/x))-(99)=0
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2x-(+5/x))-99=0
We multiply all the terms by the denominator
(2x-(+5-99*x))=0
We calculate terms in parentheses: +(2x-(+5-99*x)), so:We get rid of parentheses
2x-(+5-99*x)
We add all the numbers together, and all the variables
2x-(-99x+5)
We get rid of parentheses
2x+99x-5
We add all the numbers together, and all the variables
101x-5
Back to the equation:
+(101x-5)
101x-5=0
We move all terms containing x to the left, all other terms to the right
101x=5
x=5/101
x=5/101
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