(2x-0.8)xX=

Solution for (2x-0.8)xX= equation:

(2x-0.8)xx=

We move all terms to the left:

(2x-0.8)xx-()=0

We add all the numbers together, and all the variables

(2x-0.8)xx=0

We multiply parentheses

2x^2-0.8x=0

a = 2; b = -0.8; c = 0;
Δ = b2-4ac
Δ = -0.82-4·2·0
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{0.64}}{2*2}=\frac{0.8-\sqrt{0.64}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{0.64}}{2*2}=\frac{0.8+\sqrt{0.64}}{4}
$