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(2x-1)(-x+5)=0

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Solution for (2x-1)(-x+5)=0 equation: 



(2x-1)(-x+5)=0

We add all the numbers together, and all the variables

(2x-1)(-1x+5)=0

We multiply parentheses ..

(-2x^2+10x+x-5)=0

We get rid of parentheses

-2x^2+10x+x-5=0

We add all the numbers together, and all the variables

-2x^2+11x-5=0

a = -2; b = 11; c = -5;
Δ = b2-4ac
Δ = 112-4·(-2)·(-5)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{81}=9


x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*-2}=\frac{-20}{-4}
=+5



x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*-2}=\frac{-2}{-4}
=1/2

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