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(2x-1)(16+4x)=0
We add all the numbers together, and all the variables
(2x-1)(4x+16)=0
We multiply parentheses ..
(+8x^2+32x-4x-16)=0
We get rid of parentheses
8x^2+32x-4x-16=0
We add all the numbers together, and all the variables
8x^2+28x-16=0
a = 8; b = 28; c = -16;
Δ = b2-4ac
Δ = 282-4·8·(-16)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-36}{2*8}=\frac{-64}{16} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+36}{2*8}=\frac{8}{16} =1/2 $
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