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(2x-1)(2x+1)=4x*4x+4x+2
We move all terms to the left:
(2x-1)(2x+1)-(4x*4x+4x+2)=0
We add all the numbers together, and all the variables
(2x-1)(2x+1)-(4x+4x*4x+2)=0
We use the square of the difference formula
4x^2-(4x+4x*4x+2)-1=0
We get rid of parentheses
4x^2-4x-4x*4x-2-1=0
We add all the numbers together, and all the variables
4x^2-4x-4x*4x-3=0
Wy multiply elements
4x^2-16x^2-4x-3=0
We add all the numbers together, and all the variables
-12x^2-4x-3=0
a = -12; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-12)·(-3)
Δ = -128
Delta is less than zero, so there is no solution for the equation
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