(2x-1)(2x+1)=4x2+2x-5

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Solution for (2x-1)(2x+1)=4x2+2x-5 equation: 



(2x-1)(2x+1)=4x^2+2x-5

We move all terms to the left:

(2x-1)(2x+1)-(4x^2+2x-5)=0

We use the square of the difference formula

4x^2-(4x^2+2x-5)-1=0

We get rid of parentheses

4x^2-4x^2-2x+5-1=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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