(2x-1)(2x+1)=4x2+2x-5

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Solution for (2x-1)(2x+1)=4x2+2x-5 equation:



(2x-1)(2x+1)=4x^2+2x-5
We move all terms to the left:
(2x-1)(2x+1)-(4x^2+2x-5)=0
We use the square of the difference formula
4x^2-(4x^2+2x-5)-1=0
We get rid of parentheses
4x^2-4x^2-2x+5-1=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2

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