(2x-1)(2x-1)=8+(2x+1)(2x+1)

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Solution for (2x-1)(2x-1)=8+(2x+1)(2x+1) equation: 



(2x-1)(2x-1)=8+(2x+1)(2x+1)

We move all terms to the left:

(2x-1)(2x-1)-(8+(2x+1)(2x+1))=0

We multiply parentheses ..

(+4x^2-2x-2x+1)-(8+(2x+1)(2x+1))=0



We calculate terms in parentheses: -(8+(2x+1)(2x+1)), so:

8+(2x+1)(2x+1)

determiningTheFunctionDomain
(2x+1)(2x+1)+8

We multiply parentheses ..

(+4x^2+2x+2x+1)+8

We get rid of parentheses

4x^2+2x+2x+1+8

We add all the numbers together, and all the variables

4x^2+4x+9

Back to the equation:

-(4x^2+4x+9)



We get rid of parentheses

4x^2-4x^2-2x-2x-4x+1-9=0

We add all the numbers together, and all the variables

-8x-8=0

We move all terms containing x to the left, all other terms to the right

-8x=8

x=8/-8

x=-1

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