If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x-1)(4x+1)=(8x+1)=(8x-3)(x-2)
We move all terms to the left:
(2x-1)(4x+1)-((8x+1))=0
We multiply parentheses ..
(+8x^2+2x-4x-1)-((8x+1))=0
We calculate terms in parentheses: -((8x+1)), so:We get rid of parentheses
(8x+1)
We get rid of parentheses
8x+1
Back to the equation:
-(8x+1)
8x^2+2x-4x-8x-1-1=0
We add all the numbers together, and all the variables
8x^2-10x-2=0
a = 8; b = -10; c = -2;
Δ = b2-4ac
Δ = -102-4·8·(-2)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{41}}{2*8}=\frac{10-2\sqrt{41}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{41}}{2*8}=\frac{10+2\sqrt{41}}{16} $
| 9x+x+22=180 | | (7x+34)+x=180 | | y/2+15=7 | | 7x+34+x=180 | | F(x)=x²-3x+6 | | 4y-1=3y+2-3(3y-4) | | P^2-8p+22=6 | | 3g=g+4 | | b1+b2/2=30+8/2 | | (8+8)+2=x-2 | | -15-11x+x^2=0 | | x5+12-(2x)=0 | | -15-11x+x^2=- | | x5+12=2x | | (4x+9)(x)=440 | | 3x−2=6x+5 | | 4x^2+108x+360=0 | | -5x-34=2(x-1)+3 | | -3x+32=2(5x+3) | | 3(2x+2)-4=4x-12 | | 2(2x-1)=-46 | | 4x-32=4(4x+4) | | x^2-3x-6.75=0 | | 11a=18a+21a+9= | | 5x-39=3(3x-3)+2 | | -24=2(4x-4) | | 2(4x-4)=5x-29 | | 7x-7=6x-17 | | 13x+15=3x-65 | | 123+12/x+5=1 | | 0.7*x+0.3*9=6 | | 4x-2=10(x=0) |