(2x-1)(4x+2)=(8x+3)(x-4)

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Solution for (2x-1)(4x+2)=(8x+3)(x-4) equation: 



(2x-1)(4x+2)=(8x+3)(x-4)

We move all terms to the left:

(2x-1)(4x+2)-((8x+3)(x-4))=0

We multiply parentheses ..

(+8x^2+4x-4x-2)-((8x+3)(x-4))=0



We calculate terms in parentheses: -((8x+3)(x-4)), so:

(8x+3)(x-4)

We multiply parentheses ..

(+8x^2-32x+3x-12)

We get rid of parentheses

8x^2-32x+3x-12

We add all the numbers together, and all the variables

8x^2-29x-12

Back to the equation:

-(8x^2-29x-12)



We get rid of parentheses

8x^2-8x^2+4x-4x+29x-2+12=0

We add all the numbers together, and all the variables

29x+10=0

We move all terms containing x to the left, all other terms to the right

29x=-10

x=-10/29

x=-10/29

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