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(2x-1)(4x+6)=0
We multiply parentheses ..
(+8x^2+12x-4x-6)=0
We get rid of parentheses
8x^2+12x-4x-6=0
We add all the numbers together, and all the variables
8x^2+8x-6=0
a = 8; b = 8; c = -6;
Δ = b2-4ac
Δ = 82-4·8·(-6)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*8}=\frac{-24}{16} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*8}=\frac{8}{16} =1/2 $
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