(2x-1)(5x-1)=(5x-2)(2x+3)

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Solution for (2x-1)(5x-1)=(5x-2)(2x+3) equation: 



(2x-1)(5x-1)=(5x-2)(2x+3)

We move all terms to the left:

(2x-1)(5x-1)-((5x-2)(2x+3))=0

We multiply parentheses ..

(+10x^2-2x-5x+1)-((5x-2)(2x+3))=0



We calculate terms in parentheses: -((5x-2)(2x+3)), so:

(5x-2)(2x+3)

We multiply parentheses ..

(+10x^2+15x-4x-6)

We get rid of parentheses

10x^2+15x-4x-6

We add all the numbers together, and all the variables

10x^2+11x-6

Back to the equation:

-(10x^2+11x-6)



We get rid of parentheses

10x^2-10x^2-2x-5x-11x+1+6=0

We add all the numbers together, and all the variables

-18x+7=0

We move all terms containing x to the left, all other terms to the right

-18x=-7

x=-7/-18

x=7/18

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