If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x-1)(5x-7)=(2x-1)(9-7x)
We move all terms to the left:
(2x-1)(5x-7)-((2x-1)(9-7x))=0
We add all the numbers together, and all the variables
(2x-1)(5x-7)-((2x-1)(-7x+9))=0
We multiply parentheses ..
(+10x^2-14x-5x+7)-((2x-1)(-7x+9))=0
We calculate terms in parentheses: -((2x-1)(-7x+9)), so:We get rid of parentheses
(2x-1)(-7x+9)
We multiply parentheses ..
(-14x^2+18x+7x-9)
We get rid of parentheses
-14x^2+18x+7x-9
We add all the numbers together, and all the variables
-14x^2+25x-9
Back to the equation:
-(-14x^2+25x-9)
10x^2+14x^2-14x-5x-25x+7+9=0
We add all the numbers together, and all the variables
24x^2-44x+16=0
a = 24; b = -44; c = +16;
Δ = b2-4ac
Δ = -442-4·24·16
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-20}{2*24}=\frac{24}{48} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+20}{2*24}=\frac{64}{48} =1+1/3 $
| z/9=13 | | a/9=13 | | y.02=0.3 | | 13y+4=0 | | y+13=4 | | 12x-4(x^2+2)=1 | | 2x+-1x2=15 | | 13y-4=0 | | 8+9y=2+10y | | 13+9y=6+5y | | 11y+5=9y+6 | | 13a+9=0 | | 4z+13=0 | | 3x|7=2 | | 15x^2+62x-72=0 | | 14a+2=0 | | 10a=130 | | W=1/3w+18 | | 2-8x=17-5x | | 25-7a=24-4a | | 3^x2=27x/9 | | (3x+5)(3x+5)-(4x-3)(4x-3)=0 | | 4(x−3)−3(2x+1)=18 | | 5x-3=5-3(6-2x) | | 5x=×575 | | 5x=×75 | | 7(21/11)+2(x+2)=20-(2(21/11-5) | | t=0.75(t+2.5) | | m/3=16 | | -16x^2+96x+15=0 | | 2x^2-117x+324=0 | | c+1=2c−10 |