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(2x-1)(x+1)+(x-4)(3-2x)=5
We move all terms to the left:
(2x-1)(x+1)+(x-4)(3-2x)-(5)=0
We add all the numbers together, and all the variables
(2x-1)(x+1)+(x-4)(-2x+3)-5=0
We multiply parentheses ..
(+2x^2+2x-1x-1)+(x-4)(-2x+3)-5=0
We get rid of parentheses
2x^2+2x-1x+(x-4)(-2x+3)-1-5=0
We multiply parentheses ..
2x^2+(-2x^2+3x+8x-12)+2x-1x-1-5=0
We add all the numbers together, and all the variables
2x^2+(-2x^2+3x+8x-12)+x-6=0
We get rid of parentheses
2x^2-2x^2+3x+8x+x-12-6=0
We add all the numbers together, and all the variables
12x-18=0
We move all terms containing x to the left, all other terms to the right
12x=18
x=18/12
x=1+1/2
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