(2x-1)(x+3)-(7x+4)=-3

Solution for (2x-1)(x+3)-(7x+4)=-3 equation:

(2x-1)(x+3)-(7x+4)=-3

We move all terms to the left:

(2x-1)(x+3)-(7x+4)-(-3)=0

We add all the numbers together, and all the variables

(2x-1)(x+3)-(7x+4)+3=0

We get rid of parentheses

(2x-1)(x+3)-7x-4+3=0

We multiply parentheses ..

(+2x^2+6x-1x-3)-7x-4+3=0

We add all the numbers together, and all the variables

(+2x^2+6x-1x-3)-7x-1=0

We get rid of parentheses

2x^2+6x-1x-7x-3-1=0

We add all the numbers together, and all the variables

2x^2-2x-4=0

a = 2; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·2·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*2}=\frac{8}{4}
=2
$