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(2x-1)(x-3)=(2x-3)(x-1)
We move all terms to the left:
(2x-1)(x-3)-((2x-3)(x-1))=0
We multiply parentheses ..
(+2x^2-6x-1x+3)-((2x-3)(x-1))=0
We calculate terms in parentheses: -((2x-3)(x-1)), so:We get rid of parentheses
(2x-3)(x-1)
We multiply parentheses ..
(+2x^2-2x-3x+3)
We get rid of parentheses
2x^2-2x-3x+3
We add all the numbers together, and all the variables
2x^2-5x+3
Back to the equation:
-(2x^2-5x+3)
2x^2-2x^2-6x-1x+5x+3-3=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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