(2x-1)(x-3)=(x+5)(x-1

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Solution for (2x-1)(x-3)=(x+5)(x-1 equation: 



(2x-1)(x-3)=(x+5)(x-1

We move all terms to the left:

(2x-1)(x-3)-((x+5)(x-1)=0

We multiply parentheses ..

(+2x^2-6x-1x+3)-((x+5)(x-1)=0



We calculate terms in parentheses: -((x+5)(x-1), so:

(x+5)(x-1



We get rid of parentheses

2x^2-6x-1x-((x+5)(x-1)+3=0

We multiply parentheses ..

2x^2-((+x^2-1x+5x-5)+3-6x-1x=0

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