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(2x-1)(x-5)=6x-
We move all terms to the left:
(2x-1)(x-5)-(6x-)=0
We add all the numbers together, and all the variables
(2x-1)(x-5)-(+6x)=0
We get rid of parentheses
(2x-1)(x-5)-6x=0
We multiply parentheses ..
(+2x^2-10x-1x+5)-6x=0
We get rid of parentheses
2x^2-10x-1x-6x+5=0
We add all the numbers together, and all the variables
2x^2-17x+5=0
a = 2; b = -17; c = +5;
Δ = b2-4ac
Δ = -172-4·2·5
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{249}}{2*2}=\frac{17-\sqrt{249}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{249}}{2*2}=\frac{17+\sqrt{249}}{4} $
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