(2x-1)(x/3)=4

Solution for (2x-1)(x/3)=4 equation:

(2x-1)(x/3)=4

We move all terms to the left:

(2x-1)(x/3)-(4)=0

We add all the numbers together, and all the variables

(2x-1)(+x/3)-4=0

We multiply parentheses ..

(+2x^2-1x)-4=0

We get rid of parentheses

2x^2-1x-4=0

a = 2; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·2·(-4)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{33}}{2*2}=\frac{1-\sqrt{33}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{33}}{2*2}=\frac{1+\sqrt{33}}{4}
$