(2x-1)-(18-12x)=(4x)+(6x+12)

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Solution for (2x-1)-(18-12x)=(4x)+(6x+12) equation: 



(2x-1)-(18-12x)=(4x)+(6x+12)

We move all terms to the left:

(2x-1)-(18-12x)-((4x)+(6x+12))=0

We add all the numbers together, and all the variables

(2x-1)-(-12x+18)-(4x+(6x+12))=0

We get rid of parentheses

2x+12x-(4x+(6x+12))-1-18=0



We calculate terms in parentheses: -(4x+(6x+12)), so:

4x+(6x+12)

We get rid of parentheses

4x+6x+12

We add all the numbers together, and all the variables

10x+12

Back to the equation:

-(10x+12)



We add all the numbers together, and all the variables

14x-(10x+12)-19=0

We get rid of parentheses

14x-10x-12-19=0

We add all the numbers together, and all the variables

4x-31=0

We move all terms containing x to the left, all other terms to the right

4x=31

x=31/4

x=7+3/4

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