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(2x-1)/(3x+1)=5/10
We move all terms to the left:
(2x-1)/(3x+1)-(5/10)=0
Domain of the equation: (3x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
(2x-1)/(3x+1)-(+5/10)=0
We get rid of parentheses
(2x-1)/(3x+1)-5/10=0
We calculate fractions
(20x-10)/(30x+10)+(-15x-5)/(30x+10)=0
We multiply all the terms by the denominator
(20x-10)+(-15x-5)=0
We get rid of parentheses
20x-15x-10-5=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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