(2x-1)/2=(3x+5)/3

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Solution for (2x-1)/2=(3x+5)/3 equation: 



(2x-1)/2=(3x+5)/3

We move all terms to the left:

(2x-1)/2-((3x+5)/3)=0

We calculate fractions


2x/()+(-((3x+5)*2)/()=0



We calculate terms in parentheses: +(-((3x+5)*2)/(), so:

-((3x+5)*2)/(

We multiply all the terms by the denominator


-((3x+5)*2)



We calculate terms in parentheses: -((3x+5)*2), so:

(3x+5)*2

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

-6x-10

Back to the equation:

+(-6x-10)



We get rid of parentheses

2x/()-6x-10=0

We multiply all the terms by the denominator


2x-6x*()-10*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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