(2x-1)/3+3x+4=7(x+3)/10

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Solution for (2x-1)/3+3x+4=7(x+3)/10 equation:


x in (-oo:+oo)

(2*x-1)/3+3*x+4 = (7*(x+3))/10 // - (7*(x+3))/10

(2*x-1)/3-((7*(x+3))/10)+3*x+4 = 0

(2*x-1)/3+(-7/10)*(x+3)+3*x+4 = 0

(2*x-1)/3-7/10*(x+3)+3*x+4 = 0

(2*x-1)/3+(-7/10*3*(x+3))/3+(3*3*x)/3+(3*4)/3 = 0

2*x-7/10*3*(x+3)+3*3*x+3*4-1 = 0

9*x-1/10*x-73/10+12 = 0

89/10*x-73/10+12 = 0

89/10*x+47/10 = 0

(89/10*x+47/10)/3 = 0

(89/10*x+47/10)/3 = 0 // * 3

89/10*x+47/10 = 0

89/10*x+47/10 = 0 // - 47/10

89/10*x = -47/10 // : 89/10

x = -47/10/89/10

x = -47/89

x = -47/89

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