(2x-1)/3=(3x+2)/5

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Solution for (2x-1)/3=(3x+2)/5 equation: 



(2x-1)/3=(3x+2)/5

We move all terms to the left:

(2x-1)/3-((3x+2)/5)=0

We calculate fractions


2x/()+(-((3x+2)*3)/()=0



We calculate terms in parentheses: +(-((3x+2)*3)/(), so:

-((3x+2)*3)/(

We multiply all the terms by the denominator


-((3x+2)*3)



We calculate terms in parentheses: -((3x+2)*3), so:

(3x+2)*3

We multiply parentheses

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

-9x-6

Back to the equation:

+(-9x-6)



We get rid of parentheses

2x/()-9x-6=0

We multiply all the terms by the denominator


2x-9x*()-6*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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