(2x-1)/3=(x+10)/6-4

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Solution for (2x-1)/3=(x+10)/6-4 equation: 



(2x-1)/3=(x+10)/6-4

We move all terms to the left:

(2x-1)/3-((x+10)/6-4)=0

We calculate fractions


(12x-6)/()+(-((x+10)*3)/()=0



We calculate terms in parentheses: +(-((x+10)*3)/(), so:

-((x+10)*3)/(

We multiply all the terms by the denominator


-((x+10)*3)



We calculate terms in parentheses: -((x+10)*3), so:

(x+10)*3

We multiply parentheses

3x+30

Back to the equation:

-(3x+30)



We get rid of parentheses

-3x-30

Back to the equation:

+(-3x-30)



We get rid of parentheses

(12x-6)/()-3x-30=0

We multiply all the terms by the denominator


(12x-6)-3x*()-30*()=0

We add all the numbers together, and all the variables

(12x-6)-3x*()=0

We get rid of parentheses

12x-3x*()-6=0

We move all terms containing x to the left, all other terms to the right

12x-3x*()=6

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