(2x-1)/3=(x+3)/2

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Solution for (2x-1)/3=(x+3)/2 equation: 



(2x-1)/3=(x+3)/2

We move all terms to the left:

(2x-1)/3-((x+3)/2)=0

We calculate fractions


2x/()+(-((x+3)*3)/()=0



We calculate terms in parentheses: +(-((x+3)*3)/(), so:

-((x+3)*3)/(

We multiply all the terms by the denominator


-((x+3)*3)



We calculate terms in parentheses: -((x+3)*3), so:

(x+3)*3

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

-3x-9

Back to the equation:

+(-3x-9)



We get rid of parentheses

2x/()-3x-9=0

We multiply all the terms by the denominator


2x-3x*()-9*()=0

We add all the numbers together, and all the variables

2x-3x*()=0

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