(2x-1)/4=(3x-2)/3

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Solution for (2x-1)/4=(3x-2)/3 equation: 



(2x-1)/4=(3x-2)/3

We move all terms to the left:

(2x-1)/4-((3x-2)/3)=0

We calculate fractions


2x/()+(-((3x-2)*4)/()=0



We calculate terms in parentheses: +(-((3x-2)*4)/(), so:

-((3x-2)*4)/(

We multiply all the terms by the denominator


-((3x-2)*4)



We calculate terms in parentheses: -((3x-2)*4), so:

(3x-2)*4

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

-12x+8

Back to the equation:

+(-12x+8)



We get rid of parentheses

2x/()-12x+8=0

We multiply all the terms by the denominator


2x-12x*()+8*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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