(2x-1)/4=(5x+2)/8

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Solution for (2x-1)/4=(5x+2)/8 equation: 



(2x-1)/4=(5x+2)/8

We move all terms to the left:

(2x-1)/4-((5x+2)/8)=0

We calculate fractions


2x/()+(-((5x+2)*4)/()=0



We calculate terms in parentheses: +(-((5x+2)*4)/(), so:

-((5x+2)*4)/(

We multiply all the terms by the denominator


-((5x+2)*4)



We calculate terms in parentheses: -((5x+2)*4), so:

(5x+2)*4

We multiply parentheses

20x+8

Back to the equation:

-(20x+8)



We get rid of parentheses

-20x-8

Back to the equation:

+(-20x-8)



We get rid of parentheses

2x/()-20x-8=0

We multiply all the terms by the denominator


2x-20x*()-8*()=0

We add all the numbers together, and all the variables

2x-20x*()=0

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