(2x-1)/5=(x-3)/4

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Solution for (2x-1)/5=(x-3)/4 equation:



(2x-1)/5=(x-3)/4
We move all terms to the left:
(2x-1)/5-((x-3)/4)=0
We calculate fractions
2x/()+(-((x-3)*5)/()=0
We calculate terms in parentheses: +(-((x-3)*5)/(), so:
-((x-3)*5)/(
We multiply all the terms by the denominator
-((x-3)*5)
We calculate terms in parentheses: -((x-3)*5), so:
(x-3)*5
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
We get rid of parentheses
-5x+15
Back to the equation:
+(-5x+15)
We get rid of parentheses
2x/()-5x+15=0
We multiply all the terms by the denominator
2x-5x*()+15*()=0
We add all the numbers together, and all the variables
2x-5x*()=0

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